C++ Vector Is Not A Template

C++ Vector Is Not A Template - The parameter types, as well as return type, should have at least. Web the right way for a template function to accept any std::vector by const& is: Template void some_func( std::vector<t,a> const& vec ). Or you can use a using statement: Web there is int which should not be there in your code. Template class algo{ int // here should be deleted public: Web vector is from the std namespace, so you must use std:: But when you changed the declaration with template then the class. Web when you forward declared the class as generic then at line 15 the compiler found the declaration. A header file provides the interface of the functions declared within it.

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Web the right way for a template function to accept any std::vector by const& is: Web there is int which should not be there in your code. But when you changed the declaration with template then the class. Web when you forward declared the class as generic then at line 15 the compiler found the declaration. The parameter types, as well as return type, should have at least. A header file provides the interface of the functions declared within it. Template void some_func( std::vector<t,a> const& vec ). Template class algo{ int // here should be deleted public: Or you can use a using statement: Web vector is from the std namespace, so you must use std::

Web Vector Is From The Std Namespace, So You Must Use Std::

Web the right way for a template function to accept any std::vector by const& is: Template class algo{ int // here should be deleted public: But when you changed the declaration with template then the class. Template void some_func( std::vector<t,a> const& vec ).

Web There Is Int Which Should Not Be There In Your Code.

Or you can use a using statement: The parameter types, as well as return type, should have at least. Web when you forward declared the class as generic then at line 15 the compiler found the declaration. A header file provides the interface of the functions declared within it.

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